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3 years ago

2+3(5c-17) I do not know how to simplify the expression

Mathematics

2 answers:

nalin [4]3 years ago

7 0

Answer:

15c - 49

Step-by-step explanation:

2+3(5c-17)

2+15c - 51

15c - 49

katrin2010 [14]3 years ago

3 0

2 + 3(5c - 17)

First you must distribute the 3 to the numbers inside the parentheses, which would be 5c and -17...

2 + (3 * 5c) + (3 *(-17))

2 + 15c + (-51)

2 + 15c - 51

Now you must combine like terms. Like terms are numbers that have matching variables OR are numbers with out variables. In this case the like terms are 2 and -51, since they both don't have variables

(2 + (-51)) + 15c

-49 + 15c

15c - 49

Hope this helped!

~ Just a girl in love with Shawn Mendes

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Translation: 6 units right and 3 units down<br> s(-3, 3), C(-1, 4), W(-2,-1)

sdas [7]

S (3, 0)
C (5, 1)
W (4, -4)

Explanation
You take the first number and add 6 to it and you get the new number and then you take the second number and subtract 3 from it

S: -3 + 6 = 3
S- 3 - 3 = 0

C: -1 + 6 = 5
C: 4 - 3 = 1

W: -2 + 6 = 4
W: -1 - 3 = -4

3 0

2 years ago

Rectangle JKLM is rotated 90° clockwise about the origin.

shusha [124]

Answer:

Clockwise rotation 90 ° about origin

R_{90, clockwise, origin}(x,y) -> (y,-x)

J(-4,1) therefore

R_{90, clockwise, origin}J(-4,1) -> J'(1,+4) this answer was form other person credits to him/her

Step-by-step explanation:

4 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

John invested his inheritance of $12000 in 3 different funds part in a money market fund paying 3% interest annually Parton monu

Leokris [45]

Answer:

John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

John invested his inheritance of $12,000 in three different funds: part in a money-market fund paying 3% interest annually; part in municipal bonds paying 4% annually; and the rest in mutual funds paying 7% annually. John invested $4,000 more in mutual funds than he invested in municipal bonds. The total interest earned in one year was $670. How much did he invest in each type of fund?

The explanation of the answer is now given as follows:

Let a, b and c represent the amount invested in money-market fund, municipal bonds and mutual funds respectively. Therefore, the sum of the three principal amounts can be represented as follows:

a + b + c = 12,000 ……………………….. (1)

Since John invested $4,000 more in mutual funds than he invested in municipal bonds, we have:

c = b + 4,000 ……………………………. (2)

The total amount of interest earned from each fund can be represented as follows:

0.03a + 0.04b + 0.07c = 670 ………………. (3)

Substituting equation (2) into equation (1), we have:

a + b + b + 4,000 = 12,000

a + 2b = 12,000 – 4,000

a + 2b = 8,000

a = 8,000 – 2b ……………………….. (4)

Also, substituting equation (2) into equation (3), we have:

0.03a + 0.04b + 0.07(b + 4,000) = 670

0.03a + 0.04b + 0.07b + 280 = 670

0.03a + 0.04b + 0.07b 0 = 670 – 280

0.03a + 0.11b = 390 ,,,,,,,,,,,,,,,,,,,,,, (5)

Substituting equation (4) into equation (5) and solve for b, we have:

0.03(8,000 – 2b) + 0.11b = 390

240 – 0.06b + 0.11b = 390

240 + 0.05b = 390

0.05b = 390 – 240

0.05b = 150

b = 150 / 0.05

b = 3,000

Substituting b = 3,000 into equation (2), we have:

c = 3,000 + 4,000

c = 7,000

Also, substituting b = 3,000 into equation (4), we have:

a = 8,000 – (2 * 3,000)

a = 8,000 – 6,000

a = 2,000

Therefore, John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

8 0

3 years ago

Nancy is asked to use her calculator to find the volume of a cylindrical canister that has a radius of 10.55 cm and a height of

Murljashka [212]

use the formula given:

V = pi r^2h

r = 10.55

h = 12.56

V = 3.14 x 10.55^2 x 12.56 = 4391.81 round off to 4392cm^3

answer is D 4392

7 0

3 years ago

Read 2 more answers