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3 years ago

In trapezoid ABCD with legs AB and CD , ACAD=23 dm^2. Find AABD.

Mathematics

1 answer:

Fed [463]3 years ago

6 0

In the figure, ABCD is a trapezoid with legs AB and CD.

Join AC and BD.

For the triangle CAD, from the vertex C, draw an altitude CE and for the triangle ABD, from the vertex B, draw an altitude BF.

Clearly, CE = BF = h (say) --- (1)

Note that the base of the triangles CAD and ABD are the same and is AD.

It is given that ar(CAD) = $23dm^{2}$ .

Now, ar(ABD) = $\frac{1}{2}(AD)(BF)$

= $\frac{1}{2}(AD)(CE)$ from (1)

= ar(CAD)

= $23dm^{2}$ .

Hence, area of Δ ABD = $23dm^{2}$ ..

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2 years ago

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The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

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More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

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2 years ago

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3 years ago

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3 years ago