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-Dominant- [34]
2 years ago
8

I'll mark ur answer as brainlist and please show you're workk !!​

Mathematics
1 answer:
tatyana61 [14]2 years ago
4 0

Answer:

Distance is 37 units

Step-by-step explanation:

Put it in the distance formula on my TI84 Plus CE.

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The triangles are congruent by SSS.
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a and d

Step-by-step explanation:

i took the test

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already answered

Step-by-step explanation:

go to this

brainly.com/question/14833666

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Test the series for convergence or divergence (using ratio test)​
Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
2 years ago
POSSIBLE POINTS: 50
bekas [8.4K]

Answer:

just subtrade $2.60 by 34.

Step-by-step blablab;lablablablablabla

3 0
2 years ago
7 times the difference of x and 8
Thepotemich [5.8K]

Answer:

7(x - 8)

Step-by-step explanation:

times means multiplication

difference means subtraction

7 times the difference of x and 8 -> 7 * (x - 8) -> 7(x - 8)

Simplify if needed.

7(x - 8)

~Distribute

2x - 56

Best of Luck!

8 0
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