I uploaded the answer to a file hosting. Here's link:
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The person above me is right. It’s A , you have to add
Given:
Let P= profit
let n= no. of tacos sold per day
Sol'n:
P= 3.25n-210
the profit needs to be positive, thus
3.25n>210
n>210/3.25
n> 64.615
they can only sell whole tacos, therefore they must sell at least 65 tacos to make a profit and that profit is:
P=3.25n-210
P=3.25*65 - 210
P= 211.25 -210
P= 1.25
$1.25 profit
Can you please explain this a bit better? i dont understand
We are given the following inequality:

If we replace b = 2, we get:

Now we solve for "a" first by subtracting 8 on both sides:
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Now we divide both sides by 6

Simplifying:
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Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3