Interesting question. Good to know for computer science.
Suppose you have a function like
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1

a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3

an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3
a3 = 7

a4 = a3 + 3
a4 = 7 + 3
a4 = 10

a5 = a4+ 3
a5 = 10 + 3
a5 = 13

I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16

a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.

So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.

6 0

3 years ago

Given the relation A = {(5,2), (7,4), (9,10), (x, 5)}. Which of the following values for x will make relation A a function?

bija089 [108]

It will be the first one 9

5 0

3 years ago

Theoretical Probability - Guided Practice#1 - All of the letters in the word Mississippi are written on separate pieces of paper

Naily [24]

The probability = outcome/total outcomes

The total of the outcomes is the total number of the letters of the given word, then

The total outcomes = 11

The outcome is the number of letter "s" in the word

The outcome = 4, then

The probability of "s" is

$P(s)=\frac{4}{11}$

To change it to percent multiply it by 100% and round it to the nearest 1 decimal place

$\begin{gathered} P(s)=\frac{4}{11}\times100 \\ P(s)=36.4 \end{gathered}$

The answer is 36.4%

Answer C

5 0

1 year ago

Of 3/1=6/2 then 3-1/1=

Oksi-84 [34.3K]

I'm not sure what you want with the first part (3/1=6/2)

well PEMDAS or parenthasees exponents, mult or division whichever comes first, addition subtraction, whichever comes first so

3-1/1 would be divison first
1/1=1
3-1=2

5 0

3 years ago