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mr Goodwill [35]
4 years ago
14

Factoring out the GCF 8m^2n^3-24m^2n^2 +4m^3 n

Mathematics
1 answer:
pickupchik [31]4 years ago
5 0

Answer:

\large\boxed{8m^2n^3-24m^2n^2+4m^3n=4m^2n(2n^2-6n+m)}

Step-by-step explanation:

8m^2n^3-24m^2n^2+4m^3n\\\\8m^2n^3=\boxed{(2)}\boxed{(2)}(2)\boxed{(m)}\boxed{(m)}\boxed{(n)}(n)(n)\\\\24m^2n^2=\boxed{(2)}\boxed{(2)}(2)(3)\boxed{(m)}\boxed{(m)}\boxed{(n)}(n)\\\\4m^3n=\boxed{(2)}\boxed{(2)}\boxed{(m)}\boxed{(m)}(m)\boxed{(n)}\\\\8m^2n^3-24m^2n^2+4m^3n\\\\=\boxed{(2)}\boxed{(2)}\boxed{(m)}\boxed{(m)}\boxed{(n)}\bigg((2)(n)(n)-(2)(3)(n)+(m)\bigg)\\\\=4m^2n(2n^2-6n+m)

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lara31 [8.8K]

Answer:

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Step-by-step explanation:

a. The midpoint of PQ

To calculate this, we use the midpoint formula;

(x,y) = {(x1 + x2)/2 , (y1 + y2)/2}

From the question; (x1,y1) = (-5,4) and (x2,y2) = (7,-5)

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The coordinates of the midpoint of pq is (1,-0.5)

c. Length of pq

Mathematically;

Length = √{(x2-x1)^2 + (y2-y1)^2}

Length = √{(7-(-5))^2 + (-5-4)^2}

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b. What we will use here is the internal division formula of the section formula;

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(x,y) = (mx2 + nx1)/m+ n , (my2 + ny1)/m + n

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(x1,y1) = (-5,4)

(x2,y2) = (7,-5)

So substituting these values, we have;

(x,y) = (2(7)+ 3(-5))/(2+3) , 2(-5) + 3(4)/(2+3)

(x,y) = (14 -15)/5 , (-10 + 12)/5

= (-1/5, 2/5) = (-0.2, 0.4)

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