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mr Goodwill [35]
3 years ago
14

Factoring out the GCF 8m^2n^3-24m^2n^2 +4m^3 n

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Answer:

\large\boxed{8m^2n^3-24m^2n^2+4m^3n=4m^2n(2n^2-6n+m)}

Step-by-step explanation:

8m^2n^3-24m^2n^2+4m^3n\\\\8m^2n^3=\boxed{(2)}\boxed{(2)}(2)\boxed{(m)}\boxed{(m)}\boxed{(n)}(n)(n)\\\\24m^2n^2=\boxed{(2)}\boxed{(2)}(2)(3)\boxed{(m)}\boxed{(m)}\boxed{(n)}(n)\\\\4m^3n=\boxed{(2)}\boxed{(2)}\boxed{(m)}\boxed{(m)}(m)\boxed{(n)}\\\\8m^2n^3-24m^2n^2+4m^3n\\\\=\boxed{(2)}\boxed{(2)}\boxed{(m)}\boxed{(m)}\boxed{(n)}\bigg((2)(n)(n)-(2)(3)(n)+(m)\bigg)\\\\=4m^2n(2n^2-6n+m)

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Answer:

Conclusion:

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Step-by-step explanation:

Given

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We know that the diagonals of a parallelogram bisect each other.

Therefore,

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Given RT = x and TP = 5x-28, so

x = 5x-28

5x = x+28

5x-x = 28

4x = 28

divide boh sides by 4

4x/4 = 28/4

x = 7

Thus, the value of x = 7

Similarly,

QT = TS

Given QT = 5y and TS = 2y+12, so

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divide both sides by 3

3y/3 = 12/3

y = 4

Thus, the value of y = 4

Conclusion:

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3 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

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