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Jet001 [13]
3 years ago
7

A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Bt

u/h. Evaluating electricity at $0.08 per determine the cost of electricity in a month when the refrigerator operates for 360 hours
Mathematics
1 answer:
valina [46]3 years ago
8 0

Answer:

$720

Step-by-step explanation:

Coefficient of performance of a refrigerator (COP) =\frac{desired ouput}{Required inpu}

desired out i.e energy removed = 600Bth/hr

Required input=?

2.4=\frac{600}{required inpu}

required input=\frac{600}{24}=25Btu/hr

cost of electricity per hour = $0.08

cost of electricity for 360 hours =$0.08×360=$28.8

for an input of 25Btu/hr and 360 hours

∴cost of electricity in month =$28.8×25=$720

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