A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Bt
u/h. Evaluating electricity at $0.08 per determine the cost of electricity in a month when the refrigerator operates for 360 hours
1 answer:
Answer:
$720
Step-by-step explanation:
Coefficient of performance of a refrigerator (COP) =
desired out i.e energy removed = 600Bth/hr
Required input=?
2.4=
required input==25Btu/hr
cost of electricity per hour = $0.08
cost of electricity for 360 hours =$0.08×360=$28.8
for an input of 25Btu/hr and 360 hours
∴cost of electricity in month =$28.8×25=$720
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