Answer:
3.97 x 10⁸
Step-by-step explanation:
Answer:
3/4
Step-by-step explanation:
We want to find the probability that a student has a dog given that they have a cat, this means that the information given from the side that says " does not have a cat " is irrelevant and we only look at the information from the side that says " has a cat "
Probability = favorable outcomes / total # of outcomes
Favorable outcomes = Having a cat and dog , 6 students have both a cat and dog so favorable outcomes = 6
Total # of outcomes = total # of students that have a cat whether they have a dog or not. Total # of tudents that have a cat = 6 + 2 = 8
So probability of having a dog given that they have a cat = 6/8 or 3/4
Sent a picture of the solution to the problem (s).
A) x + y = 24
B) x^2 + y^2 = 306
A) x = 24 -y
Then substituting this into B)
(24 - y)^2 +y^2 = 306
576 -48y +y^2 + y^2 = 306
2 y^2 -48y + 270 = 0
x1 = 15
x2 = 9
Answer:

Step-by-step explanation:
(3/7÷1/2) ÷ 7/8
