The answer is 10.00
s - the price of one shrub
p - the price of potting soil
p = 12.50
<span>The total bill for 1 potting soil and 5 shrubs was 62.50:
p + 5s = 62.50
12.50 + 5s = 62.50
5s = 62.50 - 12.50
5s = 50.00
s = 50.00 : 5
s = 10.00</span>
A 5% discount indicates that her total purchase amount will be decreased by 5%. Paying full price could be shown as 1.00, so we must subtract 0.05 from the full price to represent the discounted total (1.00-0.05 = 0.95).
Only one choice, D, contains this multiplier so we can be certain of this answer.
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
80 - [50 - {20/2 - (16 - 2/2) ÷ 3}]
80 - [50 - {20/2 - (15) ÷ 3}]
80 - [50 - {10 - 5}]
80 - [50 - {5}]
80 - [45]
35
