X-y=3=>x=3+y
X+2y=-6
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3+y+2y=-6
3+3y=-6
3y=-6-3
3y=-9
y=-3
X+2y=-6
X+2(-3)=-6
X-6=-6
X=0
Answer:
it would be -5
Step-by-step explanation:
You use the Pythagorean theorem which is a^2+b^2=c^2
So....
.8^2+.6^2=c^2
.64+.36=c^2
1=c^2
1=c becaaue the square root of one is one
Given:
The expressions are:



To find:
The value of given expression by using integer tiles.
Solution:
We have,

Here, both number are positive. When we add 6 and 3 positive integer tiles, we get 9 positive integer tiles as shown in the below figure. So,

Similarly,

Here, 6 is positive and -4 is negative. It means we have 6 positive integer tiles and 4 negative integer tiles.
When we cancel the positive and negative integer tiles, we get 2 positive integer tiles as shown in the below figure. So,


Here, 6 is positive and -6 is negative. It means we have 6 positive integer tiles and 6 negative integer tiles.
When we cancel the positive and negative integer tiles, we get 0 integer tiles as shown in the below figure. So,

Therefore,
.