Answer: 8200 miles
Step-by-step explanation:
Based on the question, since she wants to go for five round trips, her first round trip is fixed at 3400 and she will have 4 more additional trips. This can them be calculated as:
= 3400 + 1200x
x = additional trips = 4
We then put the value of x into the equation
= 3400 + 1200x
= 3400 + 1200(4)
= 3400 + 4800
= 8200
She'll have 8200 mile after 5 round trips
Answer:
2,000,000
Step-by-step explanation:
Simple maths, really.
65 times 2 is 130, and the population is already 500,000 with no time passing. 65 years later, the population would be 1,000,000. 65 years after that, the population would double again, so the answer would be 2 million.
Hope this helped!
![q(x) = {x}^{2} + 3x + 4](https://tex.z-dn.net/?f=q%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%2B%203x%20%2B%204%20)
_________________________________
Step(1)
To find q(a) we just need to put a instead of x in q(x) function.
Let's do it...
![q(a) = {a}^{2} + 3a + 4](https://tex.z-dn.net/?f=q%28a%29%20%3D%20%20%7Ba%7D%5E%7B2%7D%20%2B%203a%20%2B%204%20)
Multiply sides by -2 :
![- 2q(a) = - 2( {a}^{2} + 3a + 4)](https://tex.z-dn.net/?f=%20-%202q%28a%29%20%3D%20%20-%202%28%20%7Ba%7D%5E%7B2%7D%20%2B%203a%20%2B%204%29%20)
![- 2q(a) = - 2 {a}^{2} - 6a - 8](https://tex.z-dn.net/?f=%20-%202q%28a%29%20%3D%20%20-%202%20%7Ba%7D%5E%7B2%7D%20-%206a%20-%208%20)
_________________________________
Step (2)
To find q(a+1) we just need to put a+1 instead of x in q(x) function.
Let's do it...
![q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\](https://tex.z-dn.net/?f=q%28a%20%2B%201%29%20%3D%20%20%28%7Ba%20%2B%201%7D%29%5E%7B2%7D%20%2B%203%28a%20%2B%201%29%20%2B%204%20%5C%5C%20%20)
![q(a + 1) = {a}^{2} + 2a + 1 + 3a + 3 + 4 \\](https://tex.z-dn.net/?f=q%28a%20%2B%201%29%20%3D%20%20%7Ba%7D%5E%7B2%7D%20%2B%202a%20%2B%201%20%2B%203a%20%2B%203%20%2B%204%20%5C%5C%20%20)
![q(a + 1) = {a}^{2} + 5a + 8](https://tex.z-dn.net/?f=q%28a%20%2B%201%29%20%3D%20%20%7Ba%7D%5E%7B2%7D%20%2B%205a%20%2B%208%20)
_________________________________
Step (3)
![q(a + 1) - 2q(a) =](https://tex.z-dn.net/?f=q%28a%20%2B%201%29%20-%202q%28a%29%20%3D%20)
![{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 = \\](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%2B%205a%20%2B%208%20-%202%20%7Ba%7D%5E%7B2%7D%20-%206a%20-%208%20%3D%20%20%5C%5C%20%20%20)
![- {a}^{2} - a = - a(a + 1)](https://tex.z-dn.net/?f=%20-%20%20%7Ba%7D%5E%7B2%7D%20-%20a%20%20%3D%20%20-%20a%28a%20%2B%201%29)
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer:
11
Step-by-step explanation:
Luke has a square patio, which means each side must have the same amount of tiles.
For example, he could have a 4 by 4 patio, 5 by 5, etc.
121 happens to be the square of 11. In other words, 11*11=121!
So, Luke can fit 11 tiles along each side of his patio.
Answer:
Add each side to get perimeter so your total is 38ft
Step-by-step explanation: