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andreyandreev [35.5K]
3 years ago
6

Which pair of points have a slope of -3/5?

Mathematics
1 answer:
Allushta [10]3 years ago
5 0

Answer:

No of these answers has a slope of  \frac{-3}{5} . My guess is B becasue its close to \frac{-3}{5} unless the 5 is supposed to be negative

Step-by-step explanation:

You have to use the slope formula \frac{y_{2} - y_{1} }{x_{2} - x_{1} }

(x_{1},y_{1}), (x_{2},y_{2})

(4, 0), (-2, 10)   \frac{10 - 0 }{-2 - 4 }= \frac{10}{6} you have to simplfy, the answer will be \frac{5}{3}

(10, -2), (0, 4)  \frac{4 - -2 }{0- 10 }= \frac{6}{-10} you have to simplfy, the answer will be \frac{3}{-5}

 (4, 2), (10, 4)  \frac{4 - 2 }{10 - 4 }= \frac{2}{6} you have to simplfy, the answer will be \frac{1}{3}

 (-4, -10),(0, -2) \frac{{-2- -10} }{0 - -4 }= \frac{8}{4} you have to simplfy, the answer will be \frac{2}{1} =2

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Explanation:

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Step-by-step explanation:

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3 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

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d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

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3 years ago
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Answer:

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Step-by-step explanation:

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