Answer:
8 seconds.
Step-by-step explanation:
To solve this question, we need to find the time, , when , that is, when the height of the object above the ground is 0 feet.
Substituting feet per second and gives the quadratic:
Since 128 is divisible by 16, it can be reduced to .
We must now solve for .
We can easily see that one answer to the equation is 0,
(we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.
The second answer, is also easy to see by inspection:
.
Therefore the object lands 8 seconds after it is thrown.
Answer:
8.
Step-by-step explanation:
x cannot be 8 because that would make the denominator zero.
Answer:
about 8.2 cm
Step-by-step explanation:
The key is to realize that the volume never changes.
The formula for the volume of a sphere is (4/3)*pi*radius^3
22/7 is being substituted in place of pi in this problem
The volume of one of the small spheres is
(4/3)*(22/7)*2^3 is about 33.524 cm^3
64 of those spheres would have a volume of 33.524*64, or about 2145 cm^3
Now, the problem is to find a sphere with a volume of 2145 cm^3
Volume = (4/3)*(22/7)*radius^3
plug in and solve
2145 = 4.1905*r^3
r^3=511.87
r is about equal to 8.2 centimeters
Answer:
I would say C
Step-by-step explanation:
1 woub. Because it is just a horizontal line with no slope