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3 years ago

Simplify.

Mathematics

1 answer:

N76 [4]3 years ago

6 0

Answer:

The answer is 60k2+k I hope this helps you!

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Which pairs of triangles appear to be congruent? Check all that apply.

Anettt [7]

Answer:

1 3 ...................rotate 3 and it is the same as 1

5 0

3 years ago

dexters weighs 50 kg. His body contains 30.8 kg of oxygen and 4. 9 kg if hydrogen. The rest is made up of other elements. How ma

andrey2020 [161]

50-(30.8+4.9)=14.3 kg.
You start with 50 then you need to subtract 30.8 and 4.9 from it. So you add them together and get 35.7. Then you subract 25.9 from 50 and get 14.3 kg.

4 0

3 years ago

Read 2 more answers

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

3 years ago

5,000+300+8 in standard form

lilavasa [31]

Answer:

5,308

Step-by-step explanation:

3 0

3 years ago

Alfred wants to waste less than 175 gallons of water this week. Every day that he waters the lawn, he wastes 59 gallons of water

victus00 [196]

L & C represent the number of days Alfred should water the lawn and wash his car respectively.
Each time he waters, there is 59 gallons used, and each time he washes car, 28 gallons used.

59L + 28C = 175 <the aim he set for himself>
59 gallons × L will then be the total amount of water he uses for watering lawn in a week.
28 gallons × C will then be the total amount of water he uses to wash his car every week.

The expression / answer : 59L + 28C = 175

Hope this helps! :)

8 0

3 years ago

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