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stealth61 [152]

3 years ago

14

WHY ISNT ANYBODY ANSWERING MY QUESTION PS HELP MEEEEE I ALWAYS GIVE BRAINLIEST 5 STARS andddd offer 25 pointsssssssssss plsss he

lp everybody just deletes my question for no reason plz help meee!

1 answer:

meriva3 years ago

6 0

Answer:

0.5 I think. because for every 2 on the x axis, it grows 1 on the y axis.

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Which conic section does the equation below describe?

Rus_ich [418]

Answer: Option C. Ellipse

Step-by-step explanation:

The general equation of an ellipse has the following form:

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} =1$

Where the point (h, k) is the center of the ellipse

In this case we have the equation

$\frac{(x-9)^2}{4} + \frac{(y+2)^2}{25} =1$

Note that its shape matches that of a ellipse with center (9, -2)

$a=\sqrt{4} \\a=2\\\\\\b=\sqrt{25}\\b=5$

Therefore the answer is the obtion C

5 0

3 years ago

Is a cub a polygon ?why or why not

Vladimir79 [104]

A cube<span> is </span>not<span> a </span>polygon<span>. </span>Polygons<span> are flat, plane figures. A </span>cube<span> is a 3- di mensional solid figure.</span>

6 0

3 years ago

Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

2 years ago

Solve for y.<br> 3x + 4y = z<br> -----------------

Georgia [21]

Answer:

y= z-3x/4

Step-by-step explanation:

4y=z-3x

y=z-3x/4

3 0

3 years ago

Find the surface area of each shipping package. Which package has the greater surface area? Does the same package have a greater

Kryger [21]

Answer:

greater area: A
no, B has the greater volume

Step-by-step explanation:

The relevant area and volume formulas are ...

A = 2(LW +H(L +W))

V = LWH

When there are multiple instances of the calculations to be done, it is convenient to let a spreadsheet do them. The results are attached.

Figure A has the larger area.

Figure B has the larger volume.

__

<em>Additional comment</em>

The more "cube-like" the prism is, the less area it will have for the same volume. Here, package B is more "cube-like" than package A. (The ratio of largest-to-smallest dimensions is smaller for package B.)

3 0

2 years ago