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ZanzabumX [31]
3 years ago
14

The following two triangles are similar. Find x.

Mathematics
2 answers:
NikAS [45]3 years ago
7 0
The answer to your question is D.7
lisabon 2012 [21]3 years ago
3 0

Answer:

D. 7

Step-by-step explanation:

Since the two triangles are similar the ratio will be

56 : x

48 : 6

We can simplify 48 : 6 as 8 : 1 by dividing both 48 and 6 by the factor 6. Then you can compare 8 : 1 and 56 : x. When you do this you'll see that to go from 8 to 56 you have to multiply by 7. So you have to do that for 1 as well. 1 x 7 = 7. Therefore x = 7.

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Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

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