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vlada-n [284]
3 years ago
11

Express the radical using the imaginary unit, i.

Mathematics
1 answer:
Trava [24]3 years ago
5 0

The foundation of imaginary numbers is that i = \sqrt{-1}.

When simplifying radicals involving square roots of negative numbers, your first step is to separate the negative from the number and turn it into i.

    \begin{aligned}\sqrt{-14} &= \sqrt{-1 \cdot 14}\\[0.5em] &= \sqrt{-1 }\cdot \sqrt{14}\\[0.5em] &= i\cdot \sqrt{14}\end{aligned}

At this point, you can turn to the \sqrt{14} and decide if this can be simplified or not.  (Ask youself if there are any perfect squares that divide into 14.)

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| 7 + m | - 4 > 8
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Answer:

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Step-by-step explanation:

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\displaystyle \large{ |7 + m|  - 4 > 8}

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\displaystyle \large{ |7 + m|  - 4 + 4 > 8 + 4} \\  \displaystyle \large{ |7 + m|  > 12}

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\displaystyle \large{ |a|  =  \sqrt{ {a}^{2} } }

Given a = any expressions and b = any positive numbers, zero or any expressions.

\displaystyle \large{ |a|  =  b \longrightarrow a =  \pm b}

From the Inequality, change > to equal

\displaystyle \large{ 7 + m   =   \pm12}

Subtract 7 both sides.

\displaystyle \large{  7 - 7 + m   =  \pm12 - 7} \\ \displaystyle \large{  m   =   \pm12 - 7}

±12-7 can be 12-7 = 5 or -12-7 = -19

\displaystyle \large{  m   =   5, - 19}

Refer to the attachment. The region is when the absolute value function is greater than constant function y = 12 or a blue horizontal line.

Since the absolute graph is above constant graph when x > 5 and x <-19.

Therefore,

\displaystyle \large{  m    >  5, m < - 19}

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