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vlada-n [284]
3 years ago
11

Express the radical using the imaginary unit, i.

Mathematics
1 answer:
Trava [24]3 years ago
5 0

The foundation of imaginary numbers is that i = \sqrt{-1}.

When simplifying radicals involving square roots of negative numbers, your first step is to separate the negative from the number and turn it into i.

    \begin{aligned}\sqrt{-14} &= \sqrt{-1 \cdot 14}\\[0.5em] &= \sqrt{-1 }\cdot \sqrt{14}\\[0.5em] &= i\cdot \sqrt{14}\end{aligned}

At this point, you can turn to the \sqrt{14} and decide if this can be simplified or not.  (Ask youself if there are any perfect squares that divide into 14.)

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Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e
malfutka [58]

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

340-290\\=50

Hence, Bob sold 50 fewer muffins than Diana.

3 0
3 years ago
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Two cars leave from a town at the same time traveling in opposite directions. One travels 5 mph faster than the other. In 3 hour
Doss [256]

Let the slower cars speed equal X.

The faster cars speed would be X+5 ( 5 mph faster).


They traveled for 3 hours

Multiply the time of travel by speed to equal the number of miles traveled.

So you have:

3X + 3(X+5) = 267 miles

Simplify the left side:

3X + 3X+15 = 267

Combine like terms:

6x + 15 = 267

Subtract 15 from each side"

6x = 252

Divide each side by 6:

x = 252 / 6

X = 42


The slower car was traveling at 42 mph and the faster car was traveling at 47 mph.




7 0
3 years ago
Given g(x)=3x−2find the value of g(2)
nevsk [136]

Answer:

The answer is 4

Step-by-step explanation:

g(x)=3x-2

g(2)=3*2-2=6-2=4

5 0
3 years ago
Apply the method of undetermined coefficients to find a particular solution to the following system.wing system.
jarptica [38.1K]
  • y''-y'+y=\sin x

The corresponding homogeneous ODE has characteristic equation r^2-r+1=0 with roots at r=\dfrac{1\pm\sqrt3}2, thus admitting the characteristic solution

y_c=C_1e^x\cos\dfrac{\sqrt3}2x+C_2e^x\sin\dfrac{\sqrt3}2x

For the particular solution, assume one of the form

y_p=a\sin x+b\cos x

{y_p}'=a\cos x-b\sin x

{y_p}''=-a\sin x-b\cos x

Substituting into the ODE gives

(-a\sin x-b\cos x)-(a\cos x-b\sin x)+(a\sin x+b\cos x)=\sin x

-b\cos x+a\sin x=\sin x

\implies a=1,b=0

Then the general solution to this ODE is

\boxed{y(x)=C_1e^x\cos\dfrac{\sqrt3}2x+C_2e^x\sin\dfrac{\sqrt3}2x+\sin x}

  • y''-3y'+2y=e^x\sin x

\implies r^2-3r+2=(r-1)(r-2)=0\implies r=1,r=2

\implies y_c=C_1e^x+C_2e^{2x}

Assume a solution of the form

y_p=e^x(a\sin x+b\cos x)

{y_p}'=e^x((a+b)\cos x+(a-b)\sin x)

{y_p}''=2e^x(a\cos x-b\sin x)

Substituting into the ODE gives

2e^x(a\cos x-b\sin x)-3e^x((a+b)\cos x+(a-b)\sin x)+2e^x(a\sin x+b\cos x)=e^x\sin x

-e^x((a+b)\cos x+(a-b)\sin x)=e^x\sin x

\implies\begin{cases}-a-b=0\\-a+b=1\end{cases}\implies a=-\dfrac12,b=\dfrac12

so the solution is

\boxed{y(x)=C_1e^x+C_2e^{2x}-\dfrac{e^x}2(\sin x-\cos x)}

  • y''+y=x\cos(2x)

r^2+1=0\implies r=\pm i

\implies y_c=C_1\cos x+C_2\sin x

Assume a solution of the form

y_p=(ax+b)\cos(2x)+(cx+d)\sin(2x)

{y_p}''=-4(ax+b-c)\cos(2x)-4(cx+a+d)\sin(2x)

Substituting into the ODE gives

(-4(ax+b-c)\cos(2x)-4(cx+a+d)\sin(2x))+((ax+b)\cos(2x)+(cx+d)\sin(2x))=x\cos(2x)

-(3ax+3b-4c)\cos(2x)-(3cx+3d+4a)\sin(2x)=x\cos(2x)

\implies\begin{cases}-3a=1\\-3b+4c=0\\-3c=0\\-4a-3d=0\end{cases}\implies a=-\dfrac13,b=c=0,d=\dfrac49

so the solution is

\boxed{y(x)=C_1\cos x+C_2\sin x-\dfrac13x\cos(2x)+\dfrac49\sin(2x)}

7 0
3 years ago
How to write 325809 in expanded form
BartSMP [9]
Three hundred twenty five thousand eight hundred nine
7 0
4 years ago
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