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BabaBlast [244]
3 years ago
6

Rectangle ABCD has vertices A(8, 5) , B(8, 10) , C(14, 10) , and D(14, 5) . A dilation with a scale factor of 1.2 and centered a

t the origin is applied to the rectangle. Which vertex in the dilated image has coordinates of (9.6, 6) ?
A′

B′

C′

D′
Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
D Looks like it it should be it


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Which ordered pair is a solution to the system of linear equation? 2x+ 3y=6 <br> -3x+5y=10
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Answer:

<h3>x = (-2)</h3><h3>y = 2</h3>

Step-by-step explanation:

2x + 3y = 6________( 1 )

-3x + 5y = 10_______( 2 )

( 1 ) × 3 ---- 6x + 9y = 18_____( 3 )

( 2 ) × 2 ---- -6x + 10y = 20_____( 4 )

(4)  +  (3) \\ 6x + 9y  +  ( - 6x + 10y) = 20 - 18 \\ 6x + 9y  -  6x - 10y = 2 \\ y = 2

y = 2 ,

2x + 3y = 6 \\ 2x + 3(2) = 2 \\ 2x + 6 = 2 \\ 2x = 2 - 6 \\ 2x =  - 4 \\x =  \frac{ - 4}{2}  \\ x = ( - 2) \\

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Han's bank account has a balance that is overdrawn and his account balance is -$13.00. How much would he need to deposit in orde
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Answer:

$23.00

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3 years ago
A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i
Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: \frac{x}{20}+\frac{x}{12}+900= 1200 , where x is the distance.

B.  The flowerbed is 2250 feet far from the hive.

<u><em>Explanation</em></u>

Suppose, the distance of the flowerbed from the hive is x feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, Time=\frac{Distance}{Speed}

So, the time taken by the bee to reach the flowerbed = \frac{x}{20} seconds and the time taken to fly back to the hive =\frac{x}{12} seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250

Thus, the distance of the flowerbed from the hive is 2250 feet.

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