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densk [106]
3 years ago
8

What is the solution to the equation StartFraction 1 Over h minus 5 EndFraction + StartFraction 2 Over h + 5 EndFraction = Start

Fraction 16 Over h squared minus 25 EndFraction?
h = eleven-thirds
h = 5
h = 7
h = twenty-one-halves
Mathematics
2 answers:
vlabodo [156]3 years ago
7 0

Answer:

h=7

Step-by-step explanation:

djyliett [7]3 years ago
4 0

Answer:

h=7

Step-by-step explanation:

We want to solve the equation:

\frac{1}{h-5}+\frac{2}{h+5}=\frac{16}{h^2-25}

We multiply through by the LCM: h^2-25=(h+5)(h-5)

(h^2-25*\frac{1}{h-5}+(h^2-25)*\frac{2}{h+5}=\frac{16}{h^2-25}   \times(h^2-25)

Simplify to get:

h+5+2(h-5)=16

We expand to get:

h+5+2h-10=16

h+2h=16+10-53h=21

h=7

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3 years ago
A circle is centered on point b . Points a,c, and d lie on its circumference . If adc measure 61 then what does abc measure.
Elis [28]

Answer:

\angle ABC = 122^\circ

Step-by-step explanation:

Given

\angle ADC = 61^\circ

<em>See attachment for circle</em>

Required

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\angle ABC\\ is in at the center

From cyclic theorems,

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4 0
2 years ago
Solve for x: 3|x − 3| + 2 = 14
sammy [17]
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3 years ago
Read 2 more answers
Question
Arlecino [84]

Answer:

6^{4}  · 4^{4} · b^{3}

Step-by-step explanation:

Collect identical number terms to get the exponent:

6.4⋅6.4⋅6.4⋅6.4⋅b⋅b⋅b

As you can see, there are four "6s", four "4s" and three "b"s

So we got the conclusion the answer is just 6^{4}  · 4^{4} · b^{3}

5 0
1 year ago
PLEASE HELPPPPPPPP!!!!!!!
djyliett [7]
I don’t think any of them are right
6 0
2 years ago
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