0 and 1 are neither prime nor composite. A prime is any number greater than 1 that has just 1 and itself as factors. Primes can only start at x > 1
When that happens (when you start with numbers greater than one) p^2 is a composite consisting of 2 primes, so any composite will obey the law that he number will have at least 3 factors making it up -- in this case p p^2 and 1.
So the answer to the question by definition is that 0 numbers can have the property of both p and p^2 to be prime.
Basically, all you have to do is count how many 6 's you have and then write 6^4. Which is 6 to the fourth power.
Answer: (2,4) is a solution to this system
Step-by-step explanation:
The given system of equations is expressed as
y = 2x - - - - - - - - - - - 1
y = -1/2x + 5 - - - - - - - - - 2
The first step is to equate equation 1 to equation 2. It becomes
2x = - 1/2x + 5
The next step is to add - 1/2x to the left hand side and the right hand side of the equation. It becomes
2x + x/2 = - x/2 + x/2 + 5
(4x + 2)/2 = 5
The next step is to multiply the left hand side and the right hand side of the equation by 2. It becomes
(4x + 2)/2 × 2= 5 × 2
4x + 2 = 10
Subtracting 2 from the left hand side and the right hand side of the equation. It becomes
4x + 2 - 2 = 10 - 2
4x = 8
Dividing the left hand side and the right hand side of the equation by 4, It becomes
4x/4 = 8/4
x = 8/4 = 2
Substituting x = 2 into equation 1, it becomes
y = 2 × 2 = 4
9/2 that the answer ok ok
4 cups of pecans = 5 cups of walnuts
x cups of pecans = 8 cups of walnuts
CROSS MULTIPLY
4*8 =5x
5x = 32
DIVIDE BOTH SIDES BY 5
5x/5 = 32/5
x=6.4
Therefore, 6.4 cups of pecans would be added to 8 cups of walnuts
