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iren2701 [21]
3 years ago
15

Please help me thanks if u do

Mathematics
1 answer:
aniked [119]3 years ago
3 0

Answer: a

Step-by-step explanation: look at the chart

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How many real and complex roots exists for a polynomial?
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Step-by-step explanation:

whenever a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial. as an example, we'll find the roots of the polynomial..

x^5 - x^4 + x^3 - x^2 - 12x + 12.

the fifth-degree polynomial does indeed have five roots; three real, and two complex.

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3 years ago
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What are the coefficients in the expression 4x - 7y + 5 ?
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2 years ago
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agasfer [191]

Answer:

x<1

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You would just subtract 5 from both sides of the equation. The sign does not flip because you are not multiplying or dividing any negative number across the sign.  So simply x+5 (-5) < 6 (-5). On the left side the 5 would cancel out.  on the other side 6-5 is equal to 1.

Answer:  x<1

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1 year ago
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