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3 years ago

If f has a local maximum value at x = a, what would you expect the graph of f ' to look like near x = a?

1 answer:

5 0

You would expect $f$ to be increasing to the left of $x=a$ , and decreasing to the right, which corresponds to $f'$ being positive when $x$ (but near $x=a$ ) and negative when $x>a$ .

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Can somebody help me with the Math's questions with Forming and Solving Equations? Thanks

mojhsa [17]

Step-by-step explanation:

the area of the square is (x+2)^2 and the factored form of it is x^2+4x+4

since we know the area is = 7 therefore

x^2 + 4x +4 = 7 and x^2 + 4x = 3

if you want to find the value of x :

x^2+4x+4 = 7

x^2+4x -3 = 0

(x-3)(x-1)=0

x = 3 or

x = 1

5 0

2 years ago

Can you help me on this mathswatch question?

Anna007 [38]

Where is the Question? or am i just blind

4 0

2 years ago

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Hi:) I need help with part 9(ii) ? Thanks :)!

Goshia [24]

Answer:

see explanation

Step-by-step explanation:

Given

2BD = 7BT , then

2(d - b ) = 7(t - b) ← distribute both sides

2d - 2b = 7t - 7b ( add 7b to both sides )

2d + 5b = 7t, thus

2 $\left[\begin{array}{ccc}10.5\\10\\\end{array}\right]$ + 5 $\left[\begin{array}{ccc}0\\3\\\end{array}\right]$ = 7t

$\left[\begin{array}{ccc}21\\20\\\end{array}\right]$ + $\left[\begin{array}{ccc}0\\15\\\end{array}\right]$ = 7t

$\left[\begin{array}{ccc}21\\35\\\end{array}\right]$ = 7t , thus

t = $\frac{1}{7}$ $\left[\begin{array}{ccc}21\\35\\\end{array}\right]$ = $\left[\begin{array}{ccc}3\\5\\\end{array}\right]$

Hence T = (3, 5 )

8 0

2 years ago

Read 2 more answers

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n

Svetradugi [14.3K]

Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

The null hypothesis is $H_o : p = 0.015$

The alternative hypothesis is $H_a : p < 0.015$

The sample size is n= 150

Generally in order to use normal sampling distribution

The value $np \ge 5$

$np = 0.015 * 150$

$np = 2.25$

Given that $np < 5$ normal sampling distribution can not be used

8 0

3 years ago

Need some help please

zaharov [31]

Answer:

Step-by-step explanation:

number 2

6 0

2 years ago