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kogti [31]
3 years ago
6

2b^2x^2+3a^2y^2=a^2b^2 for b^2

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

{b}^{2}  =  \frac{3 {a}^{2}  {y}^{2} }{ {a}^{2}  - 2 {x}^{2} }

Step-by-step explanation:

We want to solve for b² in

2 {b}^{2}  {x}^{2}  + 3 {a}^{2}  {y}^{2}  =  {a}^{2}  {b}^{2}

Combine terms containing b²

3 {a}^{2}  {y}^{2}  =  {a}^{2}  {b}^{2}  - 2 {b}^{2}  {x}^{2}

Factor b² to get:

3 {a}^{2}  {y}^{2}  =  ({a}^{2} - 2 {x}^{2}) {b}^{2}

Divide by a² -2b²

{b}^{2}  =  \frac{3 {a}^{2}  {y}^{2} }{ {a}^{2}  - 2 {x}^{2} }

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I don't understand this question at all please help if you do
lorasvet [3.4K]

Answer:

Answer is \frac{4}{3}

Step-by-step explanation:

To find the interval of x. Use our equations to equal each other.

-x^2+2x=y,y=0

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\int\limits^2_0 {-x^2+2x} \, dx

Integrate.

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Bezzdna [24]

If you are looking to find the value of x then you have to use distributive property.

1st: multiply -3 by 2x and 4                -3(2x+4)

                                                             -6x -12

2nd: do the same thing on the other side which is multiply 3 by x and -6

                             3(x-6)

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3 years ago
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