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2 years ago

Can someone help me with this ?

Mathematics

1 answer:

Whitepunk [10]2 years ago

6 0

Answer:

x = 25

Step-by-step explanation:

Looking at the triangle we know that it is a right triangleor a 90⁰ triangle.

(2x + 15)⁰ + x⁰ = 90⁰

2x + 15⁰ + x⁰ = 90⁰

2x + x + 15⁰ = 90⁰

3x + 15⁰ = 90⁰

3x + 15⁰ - 15⁰ = 90⁰ - 15⁰

3x = 75⁰

3x / 3 = 75⁰ / 3

x = 25⁰

Now plug the x value in the missing angles.

2x + 15⁰

2(25⁰) + 15⁰

50⁰ + 15⁰

65⁰

According to the sum of triangle, all angles add up to 180⁰. Even though this is a right triangle, it should add up 180⁰ in order to be a triangle.

65⁰ + 25⁰ + 90⁰ = 180⁰

Hope this helps and stay safe, happy, and healthy, thank you :) !!

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asambeis [7]

Answer:

We conclude that there is a difference in seat belt use.

Step-by-step explanation:

We are given that of 1,000 drivers 16-24 years old, 79% said they buckle up, whereas 924 of 1,100 drivers 25-69 years old said they did.

Let $p_1$ = population proportion of drivers 16-24 years old who buckle up .

$p_2$ = population proportion of drivers 25-69 years old who buckle up .

So, Null Hypothesis, $H_0$ : $p_1-p_2$ = 0 {means that there is no significant difference in seat belt use}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq$ 0 {means that there is a difference in seat belt use}

The test statistics that would be used here Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers 16-24 years old who buckle up = 79%

$\hat p_2$ = sample proportion of drivers 25-69 years old who buckle up = $\frac{924}{1100}$ = 84%

$n_1$ = sample of 16-24 years old drivers = 1000

$n_2$ = sample of 25-69 years old drivers = 1100

So, test statistics = $\frac{(0.79-0.84)-(0)}{\sqrt{\frac{0.79(1-0.79)}{1000}+\frac{0.84(1-0.84)}{1100} } }$

= -2.946

The value of z test statistics is -2.946.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a difference in seat belt use.

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A rectangle has a permeter of 64 inches and a length of 22 inches Which equation can you solve to find the width?

Zina [86]

Answer:

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3 years ago

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jeka57 [31]

Answer

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Add 6.71 on both sides of the eqution

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39.71 = p

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