One student is selected at random from a group of 12 freshman, 16 sophomores,

Mathematics

1 answer:

ycow [4]3 years ago

4 0

A because it’s less likely to be a freshman

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Solve for c. 3 − 7c − 20c = 7(–7c − 19) + 14c c =

OleMash [197]

Answer:

$\boxed{c = -17}$

Step-by-step explanation:

$= > 3 - 7c - 20c = 7( - 7c - 19) + 14c \\ \\ = > 3 - 27c = ( - 7c \times 7) - (7 \times 19) + 14c \\ \\ = > 3 - 27c = - 49c - 133 + 14c \\ \\ = > 3 - 27c = - 35c - 133 \\ \\ = > 3 - 27c + 35c = - 133 \\ \\ = > 3 + 8c = - 133 \\ \\ = > 8c = - 133 - 3 \\ \\ = > 8c = - 136 \\ \\ = > c = - \frac{136}{8} \\ \\ = > c = - 17$

7 0

3 years ago

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What is 6(-7+6i)(-4+2i)?

cricket20 [7]

6-2-1=185666iiiiy6663636

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3 years ago

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b

storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so $\mu = 145, \sigma = 25$ .