Systems of equations y=2x+3 y=-x-9

Mathematics

2 answers:

Anni [7]3 years ago

8 0

Answer:

(-4,-5)

Step-by-step explanation:

$y=2x+3\\y=-x-9=>Multiply(2)=>2y=-2x-18\\\\Add\\3y = -15=>y =-5\\\\Substitute\\x=-y-9=>x=-4$

Jobisdone [24]3 years ago

3 0

Answer:

vhguh

Step-by-step explanation:

cfyyghuijofdrr5xtu

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Sauron [17]

Answer:

$=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}$

the third option is your answer

Step-by-step explanation:

$\frac{5}{a-3}+\frac{3}{a+3}\\\mathrm{Least\:Common\:Multiplier\:of\:}a-3,\:a+3:\quad \left(a-3\right)\left(a+3\right)\\\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}\\=\frac{5\left(a+3\right)}{\left(a-3\right)\left(a+3\right)}+\frac{3\left(a-3\right)}{\left(a+3\right)\left(a-3\right)}\\\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{5\left(a+3\right)+3\left(a-3\right)}{\left(a-3\right)\left(a+3\right)}$