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4 years ago

Systems of equations y=2x+3 y=-x-9

Mathematics

2 answers:

Anni [7]4 years ago

8 0

Answer:

(-4,-5)

Step-by-step explanation:

$y=2x+3\\y=-x-9=>Multiply(2)=>2y=-2x-18\\\\Add\\3y = -15=>y =-5\\\\Substitute\\x=-y-9=>x=-4$

Jobisdone [24]4 years ago

3 0

Answer:

vhguh

Step-by-step explanation:

cfyyghuijofdrr5xtu

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What is m∠8 if m∠4 = 50°?

r-ruslan [8.4K]

Answer:

D) 50°. You got parallel lines cut by a traversal, so angles 4 and 8 are congruent because they're corresponding angles.

Step-by-step explanation:

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3 years ago

Give all relationships between angle 1 and angle 2 select all that apply

kolbaska11 [484]

Answer:

vertical maybe if try it and see

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3 years ago

0.546 = 0.4 + ? + 0.006 Please Explain the Answer to me!

nadya68 [22]

Answer: ? = 0.14

Step-by-step explanation:

So you need to find the value that fits the question mark. This means you have to get it by itself.

To start you subtract 0.4 from 0.546, which equals .146. Then you subtract 0.006 from 0.146 to get 0.14

What it looks like mathematically :

0.546 = 0.4 + ? + 0.006

0.146= ? + 0.006

0.14=?

Hopes this helps :)

5 0

3 years ago

Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba

Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let X = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = p = 0.05.

The sample of items selected is of size, n = 150.

The random variable X follows a Binomial distribution with parameters n = 150 and p = 0.05.

According to the Central limit theorem, if a sample of large size (n > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: $\mu_{\hat p}= p=0.05$

The standard deviation of this sampling distribution is: $\sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178$

If 10 of the 150 items produced are unacceptable then the probability of this event is:

$\hat p=\frac{10}{150}=0.067$

Compute the value of $P(\hat p\leq 0.067)$ as follows:

$P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315$

*Use a z-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0

3 years ago

A metallurgist has one alloy containing 21% titanium and another containing 50% titanium. How many pounds of each alloy must he

sweet-ann [11.9K]

x = amount of 21% alloy

y = amount of 50% alloy

The metallurgist wants a combination weighing a total of 44 lb, so

x + y = 44

Each pound of either alloy contributes either 0.21 or 0.5 pound of titanium. The final product needs to be comprised of 37% titanium; weighing at 44 lb, this means it should contain 0.37 * 44 = 16.28 lb. So

0.21x + 0.5y = 16.28

From the first equation,

x + y = 44 ==> y = 44 - x

Substitute this into the second equation and solve for x:

0.21x + 0.5(44 - x) = 16.28

-0.29x = -5.72 ==> x = 19.72

Substitute this into the first equation to solve for y:

19.72 + y = 44 ==> y = 24.28

8 0

3 years ago