1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mixer [17]
2 years ago
6

11 4/5 divided by 3 1/5 A) 3 B) 3 1/2 C) 7/2 D) 4

Mathematics
1 answer:
Yuliya22 [10]2 years ago
3 0

Answer:

Step-by-step explanation:

The two given numbers both have the denominator 5,  Thus the quotient quickly reduces:

11 4/5 becomes 59/5 and 3 1/5 becomes 16/5.  Dividing the first expression by the second yields 59/16, which can't be reduced.

However, 59 = 48 + 11, so 59/16 = 48/16 + 11/16, which is approximately 3 1/2 (from either Answer B or Answer C).

The exact answer is 3 11/16; B and C are identical and are closer to 3 11/16 thn 3 or 4.

You might be interested in
.I want a way to solve this question​
Verdich [7]

Check the picture below.

so then γ ≈ 180 - 69 - 43, γ ≈ 68.

8 0
2 years ago
Please help asap!! I need help
lana66690 [7]
It would be -5 because 4- 3*12/4 = -5

Hope this helps

Have a great day/night
4 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
What is the equation for this math problem? Steven spent $90 on clothes. He bought a pair of jeans that cost $34 and spent the r
dexar [7]

Answer:

The equation for the given maths problem is $ 34 + $ 8x = $ 90  

Step-by-step explanation:

According to question :

The Total amount spent on  cloths = $ 90

The cost of a pair of jeans  = $ 34

The cost of each t-shirt pair = $ 8

The amount spent on t-shirt = $ 90 - $ 34 = $ 56

Let the number of t-shirt pair = x

So, $ 34 + $ 8x = $ 90

Or,  $ 8x = $ 90 - $ 34

∴         x = \frac{ 90 -  34}{8}

Hence The equation for the given maths problem is $ 34 + $ 8x = $ 90  Answer

8 0
3 years ago
Please help with this question
zvonat [6]
6-10+2 solve from left to right and your answer should be -2
3 0
3 years ago
Other questions:
  • The average amount of time to finish this quiz is 26 minutes with a standard deviation of 1.2 minutes. What is the probability t
    6·1 answer
  • Select all the correct answers.
    8·1 answer
  • A street promotion worker gets paid $0.10 for each flyer he hands out. His goal is to make $16 an hour. How many flyers must he
    11·2 answers
  • The length of a rectangle is 3inches more than its width if the perimeter is 42inches find the dimensions of the rectangle
    5·1 answer
  • Which of the following are binomials?
    15·2 answers
  • I could use some help!! (worth 25 points)​
    11·2 answers
  • What is 12x + 6y = 24 for ?
    10·2 answers
  • 17. A line passes through the points (0,5) and (3, 11). Which of the following is the value of y when this line passes through x
    5·1 answer
  • Given the formula : Find the amount of money accumulated if you invested $25,000 at 4.3% interest for 8 years compounded monthly
    11·1 answer
  • I use 1/12 of my salary to pay for rates and taxes,1/16 to pay for insurance and 5/6 to meet other expenses. if i have r320 left
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!