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soldier1979 [14.2K]
3 years ago
12

Make a table of ordered pairs for the equation.   y= 1 2 x−3 PLEASE HELP !!

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0
All you need to do is plug in some x values and find the correspoding y value
when x=0, y=-3
when x=1, y=9
when x=2, y=21
when x=-1, y=-15
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Which equation is not equivalent
liraira [26]

Answer:

C

Step-by-step explanation:

(2x+3)(x+4) = 2x² + 8x + 3x + 12

                  = 2x² + 11x + 12     ≠  2x² + 10x + 12

8 0
2 years ago
10 points to whoever answers this CORRECTLY and QUICKLY. Thanks
Ainat [17]
1 solution 

x = -1/2

-------------------------------------
4 0
3 years ago
GEOMETRY HELP PLEASE!!!!!!!!!!!
Setler [38]
I have the same problem. if i find the answer i will give it to you

8 0
3 years ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
3 years ago
HELP ASAP!!<br><br>What is the length of PQ?<br><br>12 km<br><br>16 km<br><br>18 km<br><br>20 km​
natima [27]

20 km is the correct answer

4 0
3 years ago
Read 2 more answers
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