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2 years ago

To decrease an amount by 4% what single multiplier would u use ??

Mathematics

2 answers:

Finger [1]2 years ago

5 0

Multiply by .96 and your answer should be given

serg [7]2 years ago

3 0

If you decrease something by 4 percent,

you are keeping (100% - 4%) or 96% of the original

so multiply by the original amount by 96 percent or .96

If you have 100 pennies, and you give 4 away ( 4 percent decrease), you still have 96 pennies. You are keeping 96 percent of what you started with. This works no matter how much you start with.

Example:

you have 40 dollars

4% decrease

40 * .04 = 1.6 take this away

40 - 1.6 = 38.4 left

you keep 96 percent

40 * .96 = 38.4 left

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8 – 6 ∙ 4 + 10 ÷ 2 =

igor_vitrenko [27]

Answer:

-11

Step-by-step explanation:

8 0

2 years ago

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Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c

faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E | F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375

P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

P ( E ) = 0.375

P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

P ( E | F ) = P ( E & F ) / P ( F )

P ( E | F ) = 0.375 / 0.6875

P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

P ( E | F' ) = P ( E & F' ) / P ( F )

P ( E | F' ) = 0 / 0.6875

P ( E | F' ) = 0

6 0

2 years ago

What is the lower quartile of the given data set

rodikova [14]

The median of the data would be (20+25)/2, which is 45/2 = 22.5.

The first quartile (Q1), the middle number between the smallest number and the median of the data set, is 9.

The second quartile (Q2) is the median of the data. (22.5)

The third quartile (Q3) the middle value between the median and the highest value of the data, is 35.

Hope this helped!

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2 years ago

Given the graph of the function f(x) below what happens to f(x) when x is a number between 0 and 1

Andrews [41]

Answer: correct answer is D.

Step-by-step explanation:

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2 years ago

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If log2(13-8x)-log2(x^2+2)=2, what is the value of (13-8x/x^2+2)

suter [353]

Answer:

Step-by-step explanation:

There is a rule for logarithms that says:

$\log(a)-\log(b)=\log(\frac{a}{b})$ .

This is actually called quotient rule and it's name is based off the right hand side of the equation there.

So you have that you can write your right hand side as:

$\log_2(\frac{13-8x}{x^2+2})$ .

So your equation is:

$\log_2(\frac{13-8x}{x^2+2})=2$

Now let's write this in the equivalent exponential notation:

$2^2=\frac{13-8x}{x^2+2}$

So the value of the given fraction is $2^2=4$ .

Note! In general, the equivalent exponential form of $\log_b(x)=y$ is $b^y=x$ .

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2 years ago