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3 years ago

Rules for adding negative and positive signs

2 answers:

8 0

<span>Positive + Positive = Positive: 5 + 4 = 9
Negative + Negative = Negative: (- 7) + (- 2) = - 9Sum of a negative and a positive number: Use the sign of the larger number and subtract(- 7) + 4 = -3
6 + (-9) = - 3
(- 3) + 7 = 4
5 + ( -3) = 2
The sign will be that of the larger number. Remember adding a negative number is the same as subtracting a positive one!</span>

katrin [286]3 years ago

4 0

A simple way to remember what sign to put is to take the sign of the higher number.

Please mark as brainliest answer

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Find the lateral surface area of the cylinder. Round your answer to the nearest tenth.

zheka24 [161]

Answer:

The answer is "The second choice".

Step-by-step explanation:

$r=6\\\\h=13 \\\\$

Formula:

$A=2\pi rh$

$=2\times 3.14 \times 6 \times 13\\\\=2\times 3.14 \times 78\\\\=3.14 \times 156\\\\=3.14 \times 156\\\\=489.84 \approx 489.8 ft^2$

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2 years ago

Robert is a high school basketball player. In a particular game, he made some three point shots and some free throws (worth one

Oksanka [162]

Answer:

let t = number of three-point shots

let f = number of free throw shots

Step-by-step explanation:

t + f = 9 (he made a total of 9 shots altogether)

3t + 1f = 23 (number of shots multiplied by their point value)

substitution method: t = 9 - f

3(9 - f) + f = 23

27 - 3f + f = 23

-2f = -4

f = 2

find 't': t + 2 = 9

t = 7

8 0

3 years ago

marsha waide borrows 5,000 and agrees to pay it back in 2 years . if the simple interst rate is 13% ,find the total amount she p

Dmitry_Shevchenko [17]

Answer:

You want to calculate the interest on $5000 at 13% interest per year after 2 year(s).

The formula we'll use for this is the simple interest formula.

Where:

P is the principal amount, $5000.00.

r is the interest rate, 13% per year, or in decimal form, 13/100=0.13.

t is the time involved, 2....year(s) time periods.

So, t is 2....year time periods.

To find the simple interest, we multiply 5000 × 0.13 × 2 to get that:

The interest is: $1300.00

Usually now, the interest is added onto the principal to figure some new amount after 2 year(s),

or 5000.00 + 1300.00 = 6300.00. For example:

If you borrowed the $5000.00, you would now owe $6300.00

8 0

3 years ago

which table represents viable solutions for y=5x, where x is the number of tickets sold for the school play a y is the amount of

STALIN [3.7K]

Given:

The given equation is:

$y=5x$

Where x is the number of tickets sold for the school play a y is the amount of money collected for the tickets.

To find:

The correct table of values from the given options.

Solution:

We know that the number of tickets and amount of money collected for the tickets cannot be negative. So, options A and B are incorrect.

We have,

$y=5x$

For $x=0$ ,

$y=5(0)$

$y=0$

For $x=10$ ,

$y=5(10)$

$y=50$

For $x=51$ ,

$y=5(51)$

$y=255$

For $x=400$ ,

$y=5(400)$

$y=2000$

In option C, all the ordered pairs (0,0), (10,50), (51,255), (400,2000) are in the table. So, option C is correct.

For $x=65$

$y=5(65)$

$y=325$

Since the ordered pair (65,350) does not satisfy the given equation, therefore the option D is incorrect.

Hence, the correct option is C.

8 0

3 years ago

Rachel runs 2km to her bus stop, and then rides 4.5 km to school. On average, the bus is 45 km/h faster than Rachel's average ru

Mice21 [21]

Answer:6.042km/h 6km/h approximately

Step-by-step explanation:

First off we have to know the formula relating speed, distance and time which is

Speed = distance/time

Now we are looking for Rachel's running speed

We are to find Rachel's running speed, so let's label is x

We are given that the distance Rachel runs to her bus stop is 2km

We were not given the time she uses to run to the bus stop

So let's label the time Rachel uses to run to her bus stop as y

So from the formula speed = distance/time

We have x = 2/y

Now we are told that the speed the bus uses to get to school is 45km/h faster than her speed used to run

So speed of bus = 45 + x

And the overall time for the whole journey is 25mins, changing this to hours, because the speed details given is in km/h we divide 25 by 60 which will give 0.417

Now if the total time is 0.417 hours, and we labeled the time for Rachel to run to the bus as y, so the time for the time for the bus to get to school will be 0.417 - y

We are also told the bus rides for 4.5km to school

So adding this together to relate the speed, distance and time of the bus with the formula speed = distance/time

We get 45 + x = 4.5/(0.417 - y)

So we have two equations

x = 2/y (1)

45+x = 4.5/(0.417-y) (2)

So putting (1) in (2) we have

45 + (2/y) = 4.5/(0.417-y)

Expanding further

(45y + 2)/y = 4.5(0.417-y)

Cross multiplying

(45y + 2)(0.417 - y) = 4.5y

Opening the brackets

18.765y - 45y2 + 0.834 - 2y = 4.5y

Collecting like terms

-45y2 + 18.765y -2y - 4.5y + 0.834 = 0

-45y2 + 12.265 + 0.834 = 0

Dividing all sides by -45 to make the coefficient of y2 1

y2 - 0.273y - 0.019 = 0

Now we have gotten a quadratic equation, and since it's with decimal numbers we can use either completing the square method of almighty formula

I'm using almighty formula her

For solving

ax2 + bx + c = 0

x = (-b +-root(b2-4ac)/2a

For our own equation, we are finding y

From our our quadratic equation

a = 1, b=-0.273, c = -0.834

you = (-(-0.273)+-root(-0.273-4(1)(-0.019))/2(1)

y = (273+-root(0.151))/2

y = (0.273+0.389)/2 or (0.273-0.389)/2

y = 0.331 or -0.085

So we use the positive answer which is 0.331, because time can't be negative

Then we put y = 0.331 in (1)

x = 2/y

x = 2/0.331

x = 6.042km/h

x = 6km/h approximately

4 0

2 years ago