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Oduvanchick [21]
3 years ago
13

A box contains 25 marbles. there are 6 blue, 2 green, 8 red, 1 yellow, and 3 orange marbles. you randomly choose 3 marbles, one

after the other. each time, you replace the marble back in the box before choosing the next one. what is the probability that the first marble is green, the second marble is red, and the third marble is blue?
Mathematics
1 answer:
Elza [17]3 years ago
5 0
I don't understand your question. You state that a box contains 25 marbles but 6+2+8+1+3= 20!!!
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Answer:

the answer would be D because meadian is what in the middle

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2 years ago
In circle C, SQ = 10 cm. Which statements about the circle are correct? Check all that apply.
lbvjy [14]

Answer: A, B, D, E

Arc PQ is congruent to arc SR.

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Arc PS measures about 13.1 cm.

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Step-by-step explanation:

4 0
2 years ago
1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

7 0
3 years ago
Pleeeaaasssee Help!!!!
jarptica [38.1K]
It’s the first one!! :)))
8 0
3 years ago
Read 2 more answers
If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)
slega [8]
The given function are
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<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
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</span>

<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
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To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>

As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
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8 0
3 years ago
Read 2 more answers
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