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WITCHER [35]
4 years ago
13

What are the solutions to the equation 7w-3 = w?

Mathematics
1 answer:
bearhunter [10]4 years ago
7 0

Answer:

w = 1/2

Step-by-step explanation:

7w-3 = w

Subtract 7w from each side

7w-7w-3 = w-7w

-3 = -6w

Divide each side by -6

-3/-6 = -6w/-6

1/2 =w

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To get Density you do 9.45 divided by 3.5 equaling 2.7 and that is the density
6 0
3 years ago
Read 2 more answers
3. (5 + 2) = (3 . 5) + (3 . 2) *
UNO [17]

Answer:

C) Distributive Property

Step-by-step explanation:

You're <em>distributing</em> in the 3 when you multiply it by the 5 and the 2 in the algebraic process:

 ➦  ➦

3•(5 + 2) = (3 • 5) + (3 • 2)

So, the 3 was <em>distributed</em> between the 5 and 2 when you multiplied.

Hence, this is the distributive property.

8 0
3 years ago
The ratio of the area between a small square of land and a large squareof land is 3: 7. Given that the total area of the two squ
lakkis [162]

Given:

The ratio of the area between a small square of land and a large square

of land is 3: 7.

Total area of the two squares of land (in sq. meter) is 4000.

Required:

The area of each square of land.

Answer:

We have the ratio of the area between a small square of land and a large square of land is 3: 7.

Let

x^

be the area of the square of land.

Then their ratio is given by,

3x^:7x^

Also given that the total area of the two squares of land (in sq.meter) is

4,000.

The area of

Therefore,

\begin{gathered} 3x^+7x^=4000 \\ \Rightarrow10x^=4000 \\ \Rightarrow x^=400 \\  \end{gathered}

Therefore,the area of small square (in sq. meter) is,

3x=3(400)=1200

and the area of large square (in sq. meter) is,

7x=7(400)=2800

Final Answer:

The area of small and large square respectively (in sq. meter) is,1200 and 2800.

7 0
1 year ago
WILL MARK BRAINLEST PLEASE HELP!!!!!!!!!
Harrizon [31]

Answer is 3.

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8 0
3 years ago
Find the product. <br> a^3b^2 • 4ab^3
attashe74 [19]

Answer:

4a^4·b^5

Step-by-step explanation:

The applicable rule of exponents is ...

  (x^a)(x^b) = x^(a+b)

The commutative and associative properties of multiplication apply, so we can write the expression as ...

  4·(a^3·a)·(b^2·b^3) = 4·a^(3+1)·b^(2+3) = 4·a^4·b^5

8 0
4 years ago
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