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ArbitrLikvidat [17]
3 years ago
11

Prove the identity. cosh(−x) = cosh(x)

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0

Answer C

Step-by-step explanation: lol idk

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Solve for f please :)
kkurt [141]
The answer is A) i think

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3 years ago
Anybody wanna bless me with $1-$5 on cashapp??? I’m down bad right now ... ($annaly99)
amm1812

Answer:

Step-by-step explanation:

I dont have cashapp sorry

8 0
2 years ago
Find the value of 216m³ - 8n³ if 6m - 2n=0 and mn=12​
mestny [16]

Answer:

0

Step-by-step explanation:

Given that,

6m - 2n=0

=>6m=2n

=>n=3m   [divide both side by 2]

& mn=12​

Now,

216c - 8n³

= 216m³- 8(3m)³

=216m³-  8 .27m³

=216m³- 216m³

=0

6 0
2 years ago
If ( 43.65 ) ( 8.79 ) / x = ( 0.4365 ) ( 87.9 ) then value of x is:
strojnjashka [21]

Answer:

  (d)  10

Step-by-step explanation:

Multiply by x and divide by its coefficient:

  (43.65)(8.79) = (0.4365)(87.9)x

  (43.65)(8.79)/((0.4365)(87.9)) = x

At this point, any calculator can give you the answer. It is, perhaps, more satisfying to work out the answer without a calculator.

  x = (43.65)/(0.4365) × (8.79)/(87.9)

In the first quotient, the numerator is 100 times the denominator; in the second, the denominator is 10 times the numerator.

  x = (100) × (1/10) = 100/10

  x = 10

_____

Moving the decimal point to the right 1 place multiplies the numerical value by 10.

5 0
3 years ago
An FM radio station broadcasts at 84 megahertz (MHz). What is the energy of each photon in Joule? Use h = 6.6 * 10 ^ (- 34) * j
iragen [17]

Answer:

E=5.544*10^{-26} J

Step-by-step explanation:

The equation for photon energy is given by:

E=hf

Where:

h=Planck\hspace{3}constant=6.6*10^{-34} \\f=Frequency\hspace{3}of\hspace{3}the\hspace{3}wave=84000000Hz

This equation telling us that the higher the frequency of the photon, the greater its energy. And the longer the photon wavelength, the lower its energy.

So, replacing the data provided in the previous equation:

E=(6.6*10^{-34} )*(84000000)=5.544*10^{-26} J

7 0
3 years ago
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