<span>1. </span><span>Original ratio of the bike and
scooter is equals to :
=> 3 : 4, where 3 is the bike and 4 is the scooter
=> 48 bikes
=> original order = 64 scooter
=> 64 / 4 = 16
however, bike is more popular than scooter, so they changed it into new ratio:
=> 5 : 2 , where 5 is equals to bikes and 2 is equals to scooter.
=> 5 x 16 = 80 bikes
=> 2 x 16 = 32 scooter.</span>
Second option: down on the left, down on the right.
Clearly when x is bigger than one the term -x^38 will dominate the result.
When absolute value of x grows, x^38 becomes a larger positive number and - x^38 a larger negative number. Then both ends of the function tend to negative infinity.
<span>Highest point = 1406.25
Number of seconds = 9.375
We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375
So let's calculate the height at t = 9.375.
y = -16t^2 + 300t
y = -16(9.375)^2 + 300(9.375)
y = -16(87.890625) + 300(9.375)
y = -1406.25 + 2812.5
y = 1406.25
So the highest point will be 1406.25 after 9.375 seconds.
Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.'
y = -16t^2 + 300t
y = -16(9.375 + e)^2 + 300(9.375 + e)
y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e)
y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e
y = 1406.25 - 16e^2
Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
We know that 
and this is the only point when sin and cos are equal lengths. Because both 
Now if the sin of 30° is a half that would mean that cos of 60° is also a half.
Hope this helps.
<u>r3t40</u>
Walter I believe is the correct answer
