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Pavlova-9 [17]
3 years ago
11

Solve the following by elimination method 11x+15y+23=0 and 7x-2y-20=0

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]

Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
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Multiply and simplify. 2x4yx⋅6xy2z3
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The given expression 2x^4yx \times 6xy^2z^3   on multiplying  is 12x^6y^3z^3

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Consider the given two expressions 2x^4yx and 6xy^2z^3

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2x^4yx \times 6xy^2z^3

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What is the width of the rectangle shown below? <br>4x + 3 <br>A = 8x2 – 10x – 12
ozzi

Answer:

<h2><em>2x-4</em></h2>

Step-by-step explanation:

Area of a rectangle = Length * Width

Given parameters

Area A = 8x2 – 10x – 12

Length of the rectangle = 4x+3

Required

Width of the rectangle.

Substituting the given parameters into the formula

8x2 – 10x – 12  = (4x+3)*width

width = 8x2 – 10x – 12 /4x+3

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Factorizing the numerator

8x² – 10x – 12

= 2(4x²-5x-6)

= 2(4x²-8x+3x-6)

= 2(4x(x-2)+3(x-2))

= 2(4x+3)(x-2)

Width = 2(4x+3)(x-2)/4x+3

Width = 2(x-2)

Width = 2x-4

<em>Hence the width of the rectangle is 2x-4</em>

8 0
2 years ago
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