Group and factor
group y's with y's and z's with z's
(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
force undistribute -1
-y(10-y)+z(10-y)
factor
(10-y)(-y+z)
(z-y)(10-y) or
(y-z)(y-10)
No of out comes =216
favorable outcome=3
<span>probability that 5 will not appear on the die=3/216</span>
36 and 32, respectively.
I am the primary school student.
