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True [87]
3 years ago
8

A collection of nickels and dimes is worth $ 9.45. If the number of dimes is doubled, the value is $16.65. How many dimes and ho

w many nickels?
Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
<span>The amount that the collections worth increased by was $7.20. That tells you how much the additional dimes are worth that was added to the $9.45. So if there is $7.20 in dimes, there are 72 dimes that were added to the collection of dimes and nickles. The 72 dimes that were added was the doubling of the number of dimes that are apart of the collection. That means that if there was 72 dimes all together, there were 35 dimes in the initial collection, which are worth $3.50, , and 35 dimes were added later. If the total collection was worth $9.45, and $3.50 of that was in dines, then the difference of $5.95, which is the amount the nickles were worth. That means that there were 19 nickles that were apart of the initial collection.</span>
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2 years ago
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




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3 years ago
What are the coordinates of the Image of point L under a Reflection across the x-axis?
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3 years ago
Find four consecutive integers with the sum of 54
Maksim231197 [3]

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3 years ago
A robot moving forward at a constant speed takes 2.5 hours to travel 1 kilometer. Moving forward at this same constant speed, it
makvit [3.9K]

Answer:

The length of the hallway is 10 m.

Step-by-step explanation:

Given:

Time taken to cover 1 km = 2.5 hours

Distance covered in 2.5 hours = 1 km

Therefore, speed of robot = \frac{\textrm{Distance}}{\textrm{TIme}}=\frac{1}{2.5}=0.4\ km/h

Now, speed is constant.

Now, time taken to cover the length of hallway = 90 s

Speed of the robot = 0.4 km/h

Converting 0.4 km/h to m/s, we multiply by the factor \frac{5}{18}. This gives,

0.4\times \frac{5}{18}=\frac{1}{9}\ m/s

Now, distance of the hallway is equal to the product of speed and time. So,

Distance of hallway = Speed \times Time

Distance of hallway = \frac{1}{9}\times 90=\frac{90}{9}=10\ m

Therefore, the length of the hallway is 10 m.

5 0
3 years ago
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