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2 years ago

Please fill in the blank

Mathematics

1 answer:

Jobisdone [24]2 years ago

8 0

So 2 to the 3rd power is 8 and 2 to the -3 power would be negative 8.Now u multiply 8 and negative 8 and u get -64.So 2 to the to the -32 power should be the answer.hope this can help u!

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the sum of three times one number, x, and five times a second number,y, is 77. if the sum of the two numbers is 19, find the two

HACTEHA [7]

Answer:

x=9, y=10. (9, 10). The two numbers are 9 and 10.

Step-by-step explanation:

3x+5y=77

x+y=19

------------------

3x+5y=77

-3(x+y)=-3(19)

---------------------

3x+5y=77

-3x-3y=-57

-------------------

2y=20

y=20/2

y=10

x+10=19

x=19-10

x=9

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3 years ago

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3 years ago

I am stuck on how to do 10 percent of $55.86

faust18 [17]

Answer:

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Step-by-step explanation:

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2 years ago

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Artyom0805 [142]

Answer:

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Step-by-step explanation:

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1 year ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

2 years ago