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BlackZzzverrR [31]
3 years ago
12

On the first day of ticket sales the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. The school took

in $52 on the second day by selling 3 senior citizen tickets and 2 child tickets. Find the price of a senior citizen ticket and the price of a child ticket.
Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer:

The answer is, senior tickets are 8 dollars each and child tickets are 14 dollars each

Step-by-step answer

On the second day they mad 52 dollars only buy having one more child meaning that children tickets cos more. First you subtract 38 to 52 (52-38). You will then get  14 and subtract 14 to 38. After you get 24 you have to divide by three to see how much each senior ticket cost. You should then get 8.  

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frutty [35]

Answer:

I think it may be C? I used desmos to graph it but I'm not 100%

4 0
2 years ago
Find the side length of X
7nadin3 [17]

Answer:

7√3

Step-by-step explanation:

We can use pythagoreans theorem to solve this

Since, we know one side, and the hypotenuse, we can solve for the other side.  

Pythagoreans theorem: a²+b²=c²

Where a and b are two sides, and c is the hypotenuse (the side opposite of the right angle)

In this triangle, 7 is the side, and 14 is the hypotenuse.

I will plug in the values into pythagoreans theorem, and then simplify:

a^{2}+b^{2} =c^{2} \\\\7^{2} +x^{2} =14^{2} \\\\49+x^{2} =196\\\\x^{2} =147\\\\x=\sqrt{147} \\\\x=\sqrt{49*3 }\\\\ x=\sqrt{7^{2} *3 }\\\\x=7\sqrt{3}

So x = 7√3

6 0
3 years ago
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
PLS HELP!!! <br> Thank You!!!
denis-greek [22]

Answer:

21 years

Step-by-step explanation:

Given

Required

Determine the years it'll take to grow to the final height

This question depicts arithmetic progression and will be solved using

Where

Substitute these values in the given formula;

Convert all fractions to decimal

Open Brackets

Collect Like Terms

Divide both sides by 1.75

Then you have your answer.

Hope this helped!!<3

8 0
2 years ago
Read 2 more answers
Kathy's lunch cost $16 which included tax. Kathy tipped 20% and reached for a $20 bill. Did she have enough money? Please show y
e-lub [12.9K]
Yes she does have enough here's my work

16 times .20 equals 3.2 and the add 3.2 to 16 and get $19.20
7 0
3 years ago
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