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Shtirlitz [24]
3 years ago
15

Dakota bought 5 breadsticks for 58 cents each and 3 coffee cakes for 84 cents each. How much did Dakota spend?

Mathematics
2 answers:
aleksandrvk [35]3 years ago
4 0
Dakota would've spent the amount of $5.42.

sesenic [268]3 years ago
4 0
58 * 5 = 290 
84 * 3 = 252

290 + 252 = 5.42 

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1. <br> Simplify: 5 + p &gt; 3<br> p -2<br> p &gt; 8
OlgaM077 [116]

Answer:

p > -2.

Step-by-step explanation:

5 + p > 3

5 - 5 + p > 3 - 5

p > -2.

7 0
3 years ago
Find the surface area of the triangular prism (above) using its net (below).
r-ruslan [8.4K]

Answer:

96 square units

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo.

My answer:

  • The length of the large rectangle is: 5
  • The width of the large rectangle is: 7

=> Area of the large rectangle = length × width  = 7*5 = 35 square units

  • The length of the middle rectangle is: 7
  • The width of the middle rectangle is: 4

=> Area of the middle rectangle = length × width  = 7*4 = 28 square units

  • The length of the small rectangle is: 7
  • The width of the small rectangle is: 3            

=> Area of the small rectangle = length × width  = 7*3 = 21 square units

Area of top and the bottom triangles =2* \frac{1}{2}bh  = 4*3 =12  

Total surface area = 35 + 28 + 21 + 12 = 96 square units

3 0
3 years ago
Read 2 more answers
Find the product of the greatest common divisor and the least common multiple of $100$ and $120.$
dem82 [27]

Answer:

100

Step-by-step explanation:

7 0
3 years ago
Use the spinner below for each of the following
spayn [35]
The answer is : impossible
3 0
3 years ago
In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th
MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

\frac{20!}{18!2!}=190

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0
3 years ago
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