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ehidna [41]
2 years ago
9

How many ways are there to put 6 balls in 3 boxes if the balls are distinguishable but the boxes are not?

Mathematics
1 answer:
FromTheMoon [43]2 years ago
5 0

This is essentially asking how many different ways to partition 6 into 3 segments.


I am assuming "no ball in a box" is not allowed.


6 can be partitioned as

(4,1,1), (3,2,1), and (2,2,2)


So, calculate each partition, we get

(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)

= 15 + 20*3 + 15*6

=165

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Step-by-step explanation:

The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)

The Explicit Rule is ...

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Explicit rule: an = 3·3^(n-1) = 3^n

Recursive rule: a[1] = 3; a[n] = 3·a[n-1]

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6. First term is a₁ = 7; common ratio is r = 28/7 = 4.

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Explicit rule: an = 7·4^(n-1)

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