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ehidna [41]
3 years ago
9

How many ways are there to put 6 balls in 3 boxes if the balls are distinguishable but the boxes are not?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0

This is essentially asking how many different ways to partition 6 into 3 segments.


I am assuming "no ball in a box" is not allowed.


6 can be partitioned as

(4,1,1), (3,2,1), and (2,2,2)


So, calculate each partition, we get

(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)

= 15 + 20*3 + 15*6

=165

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