If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
The answer to this is 6.1 days
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Step-by-step explanation:
<h2>answer </h2><h2>36</h2>
<h2>i HOPE IT'S HELP </h2>
