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2 years ago

Me podrían ayudar plz

Mathematics

1 answer:

kompoz [17]2 years ago

3 0

Answer:

7. is 50 8. 90 9 is 40

10 is 40

sorry if i am wrong i am sry

Step-by-step explanation:

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Find the number of roots for each equation.<br> 5. 5x4 + 12x3 – x2 + 3x + 5 = 0

pav-90 [236]

Answer:

The number of roots for equation $5x^4 + 12x^3 – x^2 + 3x + 5 = 0$ is 4 .

Step-by-step explanation:

Here, the given function polynomial is :

$P(x) : 5x^4 + 12x^3 – x^2 + 3x + 5 = 0$

The Fundamental Theorem of Algebra says that a polynomial of degree n will have exactly n roots (counting multiplicity).

Now here, the degree if the polynomial is 4 (highest power of variable x).

So, according to the Fundamental Theorem, the given polynomial can have AT MOST 4 roots, counting Multiplicity.

Hence, the number of roots for equation $5x^4 + 12x^3 – x^2 + 3x + 5 = 0$ is 4 .

7 0

2 years ago

Can someone help plz ?

il63 [147K]

Answer:

Step-by-step explanation:

5 0

2 years ago

If the sum of 8th and 9th terms of

mojhsa [17]

The answer is anime and chicken nuggets

4 0

2 years ago

I’d you could help I’d appreciate it

arlik [135]

Answer:grater than 8 less than 9

Step-by-step explanation:

had the same question

6 0

3 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

2 years ago

Me podrían ayudar plz​

Me podrían ayudar plz