Answer:
216
Step-by-step explanation:
Hope this helps.
The three whites:
(30 choose 1) * (29 choose 1) * (28 choose 1) = 30 * 29 * 28
The two reds:
(20 choose 1) * (19 choose 1) = 20 * 19
So, The three whites + two reds = 30 * 29 * 28 + 20 * 19 = 24740
You can write three equations in the numbers of nickels (n), dime (d), and quarters (q).
n + d + q = 23 . . . . . . . there are 23 coins total
0n +d -q = 2 . . . . . . . . .there are 2 more dimes than quarters
5n +10d +25q = 250 . .the total value is $2.50
The collection includes 11 nickels, 7 dimes, and 5 quarters.
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I used the matrix function of my calculator to solve these equations. You can find q by subtracting from the last equation five times the sum of the first two equations.
(5n +10d +25q) -5((n +d +q) +(d -q)) = (250) -5(23 +2)
25q = 125 . . . . . . . simplify
q = 5
From the second equation,
d = q +2 = 7
And from the first,
n = 23 -5 -7 = 11
Answer:
The equivalent fraction would be 4/5, in decimal .80
Step-by-step explanation: