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Savatey [412]
2 years ago
8

Equation for parabola that has points (-4,2) (0,2) (-2,3)

Mathematics
1 answer:
almond37 [142]2 years ago
4 0

Step-by-step explanation:

What is the equation of the parabola that has a vertex at

(

−

4

,

2

)

and passes through point

(

−

7

,

−

34

)

?

To solve this you need to use the vertex form of the equation of a parabola which is

y

=

a

(

x

−

h

)

2

+

k

, where

(

h

,

k

)

are the coordinates of the vertex.

Explanation:

The first step is to define your variables

h

=

−

4

k

=

2

And we know one set of points on the graph, so

x

=

−

7

y

=

−

34

Next solve the formula for

a

y

=

a

(

x

−

h

)

2

+

k

−

34

=

a

(

−

7

+

4

)

2

+

2

−

34

=

a

(

−

3

)

2

+

2

−

34

=

9

a

+

2

−

36

=

9

a

−

4

=

a

To create a general formula for the parabola you would put in the values for

a

,

h

, and

k

and then simplify.

y

=

a

(

x

−

h

)

2

+

k

y

=

−

4

(

x

+

4

)

2

+

2

y

=

−

4

(

x

2

+

8

x

+

16

)

+

2

y

=

−

4

x

2

−

32

x

−

64

+

2

So the equation of a parabola that has a vertex at

(

−

4

,

2

)

and passes through point

(

−

7

,

−

34

)

is:

y

=

−

4

x

2

−

32

x

−

62

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Step-by-step explanation:

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Murrr4er [49]

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To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have

x + y = 120 … … … … … [total volume of antifreeze solution]

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Solve the first equation for y :

y = 120 - x

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0.65x + 108 - 0.90x = 96

0.25x = 12

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6 0
1 year ago
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
3 years ago
A simple random sample of 20 third-grade children from a certain school district is selected, and each is given a test to measur
ICE Princess25 [194]

Answer:

Option C) 5.62 points  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Sample mean score = 64

Sample standard deviation, s = 12

Degree of freedom =

=n-1\\=20-1\\=19

We have to calculate margin of error for a 95% confidence interval.

Formula for margin of error:

t_{critical}\times \displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.05} = \pm 2.093  

2.093\times (\displaystyle\frac{12}{\sqrt{20}} )\\\\ =5.6161\approx 5.62  

Thus, the correct answer is

Option C) 5.62 points

4 0
3 years ago
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