Hello from Hello from MrBillDoesMath!
Answer:
False.
Discussion:
See attached file for discussion.
Thank you,
MrB
I would think 3? it should be 3 because 32*2=64 which isn’t everyone 32*3 is 96
79+12=91
P(at least 1 missed shot) = 100 - 77.6 = 22.4%
Number of times to expect al least 1 missed shot = 0.224 x 2500 = 560 times.