Y - y₁ = m(x - x₁)
y - 5 = ⁵/₆[x - (-6)]
y - 5 = ⁵/₆(x + 6)
y - 5 = ⁵/₆(x) + ⁵/₆(6)
y - 5 = ⁵/₆x + 5
+ 5 + 5
y = ⁵/₆x + 10
y - y₁ = m(x - x₁)
y - 5 = -1¹/₅[x - (-6)]
y - 5 = 1¹/₅(x + 6)
y - 5 = 1¹/₅(x) + 1¹/₅(6)
y - 5 = 1¹/₅x + 7¹/₅
+ 5 + 5
y = 1¹/₅x + 12¹/₅
10 hours : 15 logs
x hours : 9 logs
15*x = 9*10 => x=9*10/15=6 hours
With n logs,
x=n*10/15=2n/3 hours where n is the number of logs.
It’s D)115 because every straight line has to be 180
Answer:
l.h.s.
seco√(1-sin²o). (here cos²o=1-sin²o)
sec0√cos²o
seco×coso
1/coso×coso
1
r.h.s.
Answer:



Step-by-step explanation:
Given




Solving (a): The new points
To do this, we simply multiply the old points by the scale factor.
i.e.

So:



Solving (b): The graph of the original image
See attachment