3 years ago

Differentiate \[\ln \sin^2 x\]

1 answer:

7 0

Y = ln {[sin(x)]^2}

use the chain rule

y' = 1 /[sin(x)]^2 * 2sin(x)*cos(x) = 2cos(x) / sin(x) = 2 cot(x)

Answer: 2 cot(x)

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