The functions would be:
D. y=x³
We can check it out.
(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125
Answer:
Solving 14t-3t we get 22 and 3t-14t we get -22
So, 14t-3t is not equivalent to 3t-14t.
Step-by-step explanation:
We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.
<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>
Now, We check if our expressions are equivalent, by evaluating the expression for t=2.
If they are equivalent, they would have same result after evaluation.
First, put t=2 into 14t-3t
![14t-3t\\Put\:t=2\\=14(2)-3(2)\\=28-6\\=22](https://tex.z-dn.net/?f=14t-3t%5C%5CPut%5C%3At%3D2%5C%5C%3D14%282%29-3%282%29%5C%5C%3D28-6%5C%5C%3D22)
Now put t=2, into 3t-14t
![3t-14t\\Put\:t=2\\=3(2)-14(2)\\=6-28\\=-22\\](https://tex.z-dn.net/?f=3t-14t%5C%5CPut%5C%3At%3D2%5C%5C%3D3%282%29-14%282%29%5C%5C%3D6-28%5C%5C%3D-22%5C%5C)
For solving 14t-3t we get 22 and 3t-14t we get -22
So, 14t-3t is not equivalent to 3t-14t.
The rate for the first is 1 job / 35 minutes and for the second is 1 job / 15 minutes. So combined we get
r = 1/35 + 1/15
3×5×7r = 3 + 7 = 10
r = 10/(105) jobs per minute
We're interested in 1/r
1/r = 105/10 = 10.5 minutes per job
Answer: 10.5 minutes
Answer:
x = 84°
y = 96°
Step-by-step explanation:
By tangent secant theorem:
![x = \frac{1}{2} \times 168 \degree \\ \\ x =84 \degree \\ \\y = \frac{1}{2} \times (360 - 168) \degree \\ \\ y = \frac{1}{2} \times 192 \degree \\ \\ y = 96 \degree](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20168%20%5Cdegree%20%5C%5C%20%20%5C%5C%20x%20%3D84%20%5Cdegree%20%5C%5C%20%20%5C%5Cy%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%28360%20-%20168%29%20%5Cdegree%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20192%20%5Cdegree%20%5C%5C%20%20%5C%5C%20y%20%3D%20%2096%20%5Cdegree%20)