I think it is x > 5 because if you combine like terms you would get 2x-4>6 then you add 4 To 6 which is 10 then you do 10÷2 which is 5
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
Answer: m< MIH is 34°
M< AVM is 70°
And the angle of the obtuse angle formed at the intersection of AV and HI is 104°
Step-by-step explanation: starting with m<MIH, AH is parallel to MI, so that would make the same angle H has the same for I. (34°)
Next is m<AVM. The angle of m<LAH is 110°. So the angle of m<HAV (because it's supplementary of it) is 70 (110+70=180). Which makes m<AVM 70° since it's vertical to each other.
Since we got those answers, the next one you just plug it in, and the answer would be 104°