The formula you use to find the surface area of a sphere is A=4 π r^2
4×π = 12.5663706143
r = 4
4^2 = 16
12.5663706143 × 16 = 201.061929829
Final answer: the surface area is about 201 ft.
Answer:10
Step-by-step explanation:
Answer:
548, 297
Step-by-step explanation:
We can set this up as a system of equations. The first equation is for how many tickets were sold, which is x+y=845. The second equation is for the cost of the tickets, which is 3x+5.5y=3277.50. The best method for this problem (other than graphing) is elimination. First, we need to multiply one equation to get the opposite of one of the variables. The easiest one to do for this problem is x. The opposite of 3 is -3, so we have to multiply ALL of the first equation by -3. If you do this, then you get -3x-3y=-2535. Now, combine the equations:
3x + 5.5y = 3277.50
-3x -3y = -2535
________________
0x+2.5y=742.5
Now, isolate y by dividing both sides by 2.5. If you do this, you get y=297. Now, plug this in for the y in the first equation. Isolate x.
x+297=845
-297 -297
__________
0 548
x=548
Hope this helps!
Answer:
Step-by-step explanation:
Long Division
The polynomial long division implies the sequential division of each term of the dividend polynomial by the terms of the divisor polynomial. The procedure is a well-know sequence of steps from which there are two outputs: the quotient and the remainder.
We have two mathematical models, one for the total number of visitors who went to a theme park:
The other for the number of shows played at the theme park in the same period
Where x is the number of days since October 1. We are required to find the expression for the average number of visitors per show. It comes by dividing F(x) by G(x). We must perform a long division as shown below.
The average number of visitors per show is
For example, day 5
There were 175 visitors per show (on average)
Answer:
x=-2
Step-by-step explanation:
<h2>
Solve for x: </h2>
4x (+ 5-5) = -3-5
4x = -8
4x/4 = -8/4
x=-2
<h2>Checking Answer:</h2>
4(-2) + 5= -3
-8 + 5 = -3
-3 = -3
Answer is Correct.