Answer: 40000
Step-by-step explanation:
The formula to find the sample size is given by :-
, where p is the prior estimate of the population proportion.
Here we can see that the sample size is inversely proportion withe square of margin of error.
i.e. 
By the equation inverse variation, we have

Given :


Then, we have

Hence, the sample size will now have to be 4000.
Answer:
4x^2-5y
Step-by-step explanation:
4x^2-5y
We are given that a house had a value of $245000 and its value was increased by 9%. To determine how much is this value increase in dollars we need to multiply the value of the house by 9/100. We get this:

Therefore, the increase in dollars is $22050. Now, to determine the current value we need to add the increase to the previous value, we get:

Therefore, the current value of the house is $267050.
Answer:
13x-4
Step-by-step explanation:
MO=7x-4
NO=6x
MO+NO=?
7x-4+6x=13x-4
Answer:
1.5x = 6
Step-by-step explanation:
This represents 1.5 times the amounts a bucket holds. (I'm assuming you mean x when you typed z)