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Masteriza [31]
3 years ago
13

Find the sum: (3x2 + 5x − 8) + (5x2 − 13x − 5)

Mathematics
2 answers:
Neko [114]3 years ago
7 0
(3x² + 5x - 8) + (5x² - 13x - 5)

group like terms

3x² + 5x² + 5x - 13x - 8 - 5

8x² - 8x - 13
sergejj [24]3 years ago
4 0
I showed my work too. hopefully this helps

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Help me please!!!!!!
olya-2409 [2.1K]
3276800/8 = 409600 (how many bacteria in an hour)

Then just multiply that number by the amount of hours you want to solve for 

9 hours = 3686400
10 Hours = 4096000
6 0
3 years ago
To add 20.4 + 3.75 + 4.25, Crystal first added 3.75 and 4.25. Which property did Crystal use to add mentally?
evablogger [386]

Answer:

Associative Property of Addition

Step-by-step explanation:

From the list of given options, option A correctly answers the question and this is because

a + b + c = a + (b + c) --- (1)

or

a + b + c = (a + b) + c --- (2)

<em>The above illustrations only apply to Associative Property of Addition</em>

In Crystal's case:

20.4 + 3.75 + 4.25 = 20.4 + (3.75 + 4.25)

This can be compared to (1) above

Hence;

<em>Option A answers the question</em>

3 0
3 years ago
Follow the rule to find the next three numbers in the pattern. Describe the pattern using the terms even and odd Add 5: 1,6,11 _
inessss [21]
1,6,11,16,21,26 is what you would get if you add 5.
4 0
3 years ago
Dhshshsjehsjsjjsjssjsjsjsjsjsjshshdhdhdhdjdjdjdjhdbd djdhdhdjjdjdjdjdjdjd
kramer

Answer:

Dhshshshhshsjehsjsjjsjssjsjsjsjsjsjjshhdhddhhdjdjddjdjjhdhdkdhjsdfggdhjjjjd

Step-by-step explanation:

7 0
3 years ago
The time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a
leva [86]

Answer:

Step-by-step explanation:

Given that X the time to complete a standardized exam  in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.

We have 68 rule as 2/3 of total would lie within 1 std deviation, and 95 rule as nearly 95% lie within 2 std deviations from the mean.

We have std deviation = 10

Hence 2 std deviations from the mean

= Mean ±2 std deviations

=70±20

= (50,90)

Below 50, 0.25 or 2.5% would complete the exam.

3 0
3 years ago
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